a letter and a number

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a letter and a number描述

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

输入

On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).

输出

for each case, you should the result of y+f(x) on a line

样例输入

6
R 1
P 2
G 3
r 1
p 2
g 3

样例输出

19
18
10
-17
-14
-4

解题思路：

本题涉及n组数据，而每组数据开头都是字符，scanf读取字符是会先读取换行，所以应当在读取每行数据之前，用getchar将回车吃掉，否知只能读取一半数据。

程序代码：

#include<stdio.h>
int main()
{
	int n,y,i;
	char x;
	scanf("%d",&n);
	while(n--)
	{
		getchar();
		scanf("%c%d",&x,&y);
		if(x>='a'&&x<='z')
			printf("%d\n",'a'-x-1+y);
		else if(x>='A'&&x<='Z')
			printf("%d\n",x-'A'+1+y);

	}
	return 0;
}

a letter and a number

标签：style   io   ar   for   sp   数据   div   on   代码   

原文地址：http://blog.csdn.net/yzi_angel/article/details/40794017