标签:入行 std 一个 lse printf 回退 direct creat 方向
//先输入行列,在输入迷宫 以-1 -1 结束 #include<stdio.h> #include<stdlib.h> #define MAXSIZE 100 #define ERROR -1 #define OK 1 struct Direction { int incX; //增量 int incY; }; Direction direct[4] = { {0,1},{1,0},{0,-1},{-1,0} };//方向试探 struct Box { int x, y; //当前访问的迷宫格子的纵横坐标 int di; //当前方向 }; typedef struct //用Box声明栈来存放数据 { Box* base; Box* top; int stackSize; }SqStack; void InitStack(SqStack* s) { s->base = (Box *)malloc(sizeof(Box) * MAXSIZE); if (s->base == NULL) { exit(0); } s->top = s->base; s->stackSize = MAXSIZE; } void Push(SqStack* s, Box e) { if (s->top - s->base == s->stackSize) { exit(0); } *(s->top) = e; (s->top)++; } void Pop(SqStack* s, Box* e) { if (s->top == s->base) { return; } *e = *--(s->top); } int StackLen(SqStack s) { return (s.top - s.base); } int isEmptyStack(SqStack* s) //判断栈是否为空 是返回1 不是返回-1 { if (s->top == s->base) //栈为空 { return 1; } else //栈不为空 { return 0; } } int** CreatMaze(int M, int N) //初始化 { int** maze; maze = (int **)malloc(sizeof(int*) * M); //行 for (int i = 0; i < N; i++) { maze[i] = (int *)malloc(sizeof(int) * N); //列 } for (int i = 0; i < M; i++) //将边界置为1 { for (int j = 0; j < N; j++) { maze[i][j] = 1; } } for (int i = 1; i < M-1; i++) //输入 { for (int j = 1; j < N-1; j++) { scanf("%d", &maze[i][j]); } } return maze; } bool findPath(int M, int N, Direction direct[], SqStack* s) { int** maze; Box temp,e; int x, y, di; //当前正在处理的单元行列 int line, col; //将要处理的下一个单元行列 int flag = 0; maze = CreatMaze(M + 2, N + 2); //初始化 maze[1][1] = -1; temp = { 1,1,-1 }; Push(s, temp); while (!isEmptyStack(s)) //栈不为空循环继续 { Pop(s, &temp); //如果路走不通就回退 x = temp.x; y = temp.y; di = temp.di + 1; //第一步先往右边走 while (di < 4) //尝试四个方向 { line = x + direct[di].incX; col = y + direct[di].incY; if (maze[line][col] == 0) { temp = { x,y,di }; Push(s, temp); x = line; y = col; maze[line][col] = -1; if (x == M && y == N) { return true; } else { di = 0; } } else { di++; } } } return false; } int main(void) { int M, N; bool tem; SqStack s; Box e; while (1) { InitStack(&s); scanf("%d %d", &M, &N); if (M == -1) break; tem = findPath(M, N, direct, &s); if (tem) { while (s.base != s.top) { printf("%d,%d\n", s.base->x, s.base->y); s.base++; } printf("%d,%d\n", M, N); } else { printf("NO FOUND"); } } return 0; }
标签:入行 std 一个 lse printf 回退 direct creat 方向
原文地址:https://www.cnblogs.com/ZhengLijie/p/12491363.html