标签:lis else 分类 无限 not info 列表 图片 children
将数据如下输出:
上海 -青浦 -浦东 --张江 北京 -昌平
data=[ {"cat_id":3,"name":"青浦","parent_id":1}, {"cat_id": 2, "name": "张江", "parent_id": 4}, {"cat_id":4,"name":"浦东","parent_id":1}, {"cat_id":5, "name": "北京", "parent_id": 0}, {"cat_id":6, "name": "昌平", "parent_id": 5}, {"cat_id": 1, "name": "上海", "parent_id": 0}, ] res = [] def get_son(data, level=0, parent_id=0): for item in data: # 如果当前循环的parent_id=parent_id,将level等级添加到列表中 if item[‘parent_id‘] == parent_id: item[‘level‘] = level res.append(item) # 循环所有的数据 get_son(data, level+1, parent_id=item[‘cat_id‘]) return res t = get_son(data) for i in t: print(i[‘level‘]*‘-‘, i[‘name‘]) # 北京 # - 昌平 # 上海 # - 青浦 # - 浦东 # -- 张江
需求如下:
将data 数据变成lists
lists=[{‘cat_id‘: 5, ‘name‘: ‘北京‘, ‘parent_id‘: 0, ‘level‘: 0, ‘children‘: [{‘cat_id‘: 6, ‘name‘: ‘昌平‘, ‘parent_id‘: 5, ‘level‘: 1}]}, {‘cat_id‘: 1, ‘name‘: ‘上海‘, ‘parent_id‘: 0, ‘level‘: 0, ‘children‘: [{‘cat_id‘: 3, ‘name‘: ‘青浦‘, ‘parent_id‘: 1, ‘level‘: 1}, {‘cat_id‘: 4, ‘name‘: ‘浦东‘, ‘parent_id‘: 1, ‘level‘: 1, ‘children‘: [{‘cat_id‘: 2, ‘name‘: ‘张江‘, ‘parent_id‘: 4, ‘level‘: 2}]}]}]
# 2、变成这种格式 ‘‘‘ data1 = [ {"cat_id": 1, "name": "上海", "parent_id": 0, "children":[ {"cat_id":4,"name":"浦东","parent_id":1, "children":[ {"cat_id": 2, "name": "张江", "parent_id": 4}, ] } ] }, ] ‘‘‘ def get_tree(data): lists = [] tree = {} for i in data: tree[i[‘cat_id‘]] = i # 给它变成k,v的形式,k就是cat_id,v就是这个字典对象 for item in data: if item[‘parent_id‘] == 0: # 说明它是根节点 lists.append(tree[item[‘cat_id‘]]) # 将根节点的字典添加到列表中 else: if ‘children‘ not in tree[item[‘parent_id‘]]: # 判断每一个字典(对象)有没有属于自己的儿子 tree[item[‘parent_id‘]][‘children‘] = [] # 没有就给字典(该对象)添加一个新的名为children的key,并且赋值空列表 tree[item[‘parent_id‘]][‘children‘].append(tree[item[‘cat_id‘]]) # 把儿子对象添加进去 return lists # item=为一个个的字典对象 # {"cat_id":3,"name":"青浦","parent_id":1}, # {"cat_id": 2, "name": "张江", "parent_id": 4}, # {"cat_id":4,"name":"浦东","parent_id":1}, # {"cat_id":5, "name": "北京", "parent_id": 0}, # {"cat_id":6, "name": "昌平", "parent_id": 5}, # {"cat_id": 1, "name": "上海", "parent_id": 0}, # tree={ # 3:{"cat_id":3,"name":"青浦","parent_id":1}, # 2:{"cat_id": 2, "name": "张江", "parent_id": 4}, # 4:{"cat_id":4,"name":"浦东","parent_id":1}, # 5:{"cat_id":5, "name": "北京", "parent_id": 0}, # 6:{"cat_id":6, "name": "昌平", "parent_id": 5}, # 1:{"cat_id": 1, "name": "上海", "parent_id": 0}, # }
标签:lis else 分类 无限 not info 列表 图片 children
原文地址:https://www.cnblogs.com/baohanblog/p/12508217.html