深拷贝与浅拷贝

 1 class Person
 2 {
 3 private:
 4     char *m_name;
 5     int m_num;
 6 public:
 7     Person()
 8     {
 9         m_name = NULL;
10         m_num = 0;
11         cout<<"无参构造"<<endl;
12     }
13     Person(char *name,int num)
14     {
15         //为m_name申请空间
16         m_name = (char *)calloc(1,strlen(name)+1);
17         if(m_name == NULL)
18         {
19             cout<<"构造失败"<<endl;
20         }
21         cout<<" 已经申请好空间"<<endl;
22         strcpy(m_name,name);
23         m_num = num;
24         cout<<"有参构造"<<endl;
25     }
26 
27     Person(const Person &ob)//ob==>lucy
28     {
29         cout<<"拷贝构造函数"<<endl;
30         m_name = (char *)calloc(1, strlen(ob.m_name)+1);
31         cout<<"空间已被申请"<<endl;
32         strcpy(m_name, ob.m_name);
33 
34         m_num = ob.m_num;
35     }
36 
37     ~Person()
38     {
39         if(m_name != NULL)
40         {
41             cout<<"空间已被释放"<<endl;
42             free(m_name);
43             m_name = NULL;
44         }
45         cout<<"析构函数"<<endl;
46     }
47 
48     void showPerson(void)
49     {
50         cout<<"m_name = "<<m_name<<", m_num = "<<m_num<<endl;
51     }
52 };
53 
54 void test01()
55 {
56     Person lucy("lucy",100);
57     lucy.showPerson();
58 
59     //浅拷贝的问题（多次释放同一块堆区空间）
60     //通过自定义 拷贝构造函数 完成深拷贝动作
61     Person bob = lucy;//调用系统的默认拷贝构造（单纯的值拷贝）
62 }