773. 有效的字母异位词

class Solution:
    """
    @param s: string s
    @param t: string t
    @return: Given two strings s and t, write a function to determine if t is an anagram of s.
    """
    ‘‘‘
    1.循环s，如果s里面的字符在t里面的话，就移除掉s和t对应的值，replace(‘‘,‘‘,1)
    2.如果不在里面的话，那么直接返回false，最后的时候判断s和t长度是否为0，则返回True，否则False
    ‘‘‘
    def isAnagram(self,s,t):
        s = s + ‘ ‘
        while  True:
            pop_num = s[0]
            if pop_num == ‘ ‘:
                s = s.replace(‘ ‘,‘‘,1)
                break
            if pop_num not in t:
                return False
            ##否则的话，分别移除掉相同的字符
            s = s.replace(pop_num,‘‘,1)
            t = t.replace(pop_num,‘‘,1)
        if len(s) == 0 and len(t) == 0:
            return True
        return False