标签：bre 用户 不一致 open 命令 编号 register 确认密码 eva
def auth(path):
from functools import wraps
global money
def outter1(func):
@wraps(func)
def wrapper(*args, **kwargs):
import time
time1 = time.strftime(‘%Y-%m-%d %X‘)
func()
print(func.__name__, type(func.__name__))
with open(r‘{}‘.format(path), ‘a‘, encoding=‘utf-8‘) as f:
if func.__name__ == ‘money_in‘:
f.write(‘{} {} 充值 {}\n‘.format(time1, user_in, money))
if func.__name__ == ‘money_out‘:
f.write(‘{} {} 消费 {} 元\n‘.format(time1, user_in, money))
return wrapper
return outter1
def log_in():
import os, time
global login
global user_in
while True:
user = input(‘请输入账号：‘).strip()
if os.path.exists(‘{}‘.format(user)):
with open(‘{}‘.format(user), ‘r‘, encoding=‘utf-8‘) as f:
l = f.read()
if float(l) > time.time():
print(‘该用户被锁定了‘)
continue
else:
os.remove(‘{}‘.format(user))
with open(‘db.txt‘, ‘r‘, encoding=‘utf-8‘) as f5:
for line in f5:
user1, pwd1, money1 = line.strip().split(‘:‘)
if user == user1:
count = 0
while count < 3:
pwd = input(‘请输入密码：‘).strip()
if pwd == pwd1:
login = True
user_in = user
print(‘登陆成功‘)
return 1
else:
count += 1
print(‘登录失败‘)
with open(‘{}‘.format(user), ‘w‘, encoding=‘utf-8‘) as f:
f.write(str(time.time() + 300))
print(‘该用户已经被锁定了，傻叉‘)
login = False
return login
else:
print(‘没有这个用户哦‘)
def outter(func):
from functools import wraps
@wraps(func)
def wrapper(*args, **kwargs):
while True:
if login:
func()
break
else:
print(‘请登录后操作‘)
log_in()
return wrapper
def register():
tag = True
while tag:
tag1 = True
user = input(‘请输入账号：‘).strip()
if user:
with open(‘db.txt‘, ‘r‘, encoding=‘utf-8‘) as f:
for i in f:
i, *_ = i.strip().split(‘:‘)
if i == user:
tag1 = False
print(‘该用户已存在...‘)
break
if tag1:
pwd = input(‘请输入密码：‘).strip()
pwd1 = input(‘请再次输入确认密码：‘).strip()
if pwd:
if pwd == pwd1:
while tag:
money = input(‘请输入你要存的金额：‘).strip()
if money.isdigit():
with open(‘db.txt‘, ‘a‘, encoding=‘utf-8‘) as f5:
f5.write(‘{}:{}:{}\n‘.format(user, pwd, money))
print(‘注册成功‘)
tag = False
else:
print(‘金额输入有误，请输入整数‘)
else:
print(‘密码不一致‘)
else:
print(‘密码不能为空哦‘)
else:
print(‘账号不能为空哦‘)
@auth(‘daliy.txt‘)
@outter
def money_in():
while True:
money = input(‘请输入充值金额：‘).strip()
if money.isdigit():
with open(‘db.txt‘, ‘r‘, encoding=‘utf-8‘) as f, open(‘.db.txt.swap‘, ‘w‘, encoding=‘utf-8‘) as f1:
for line in f:
user1, pwd1, money1 = line.strip().split(‘:‘)
if user_in == user1:
money1 = int(money1)
money1 += int(money)
f1.write(‘{}:{}:{}\n‘.format(user1, pwd1, money1))
print(‘充值成功,充值金额为：{}‘.format(money))
else:
print(‘请输入整数数字‘)
continue
os.remove(‘db.txt‘)
os.rename(‘.db.txt.swap‘, ‘db.txt‘)
return 1
@auth(‘daliy.txt‘)
@outter
def money_out():
global money
while True:
if str(money).isdigit():
with open(‘db.txt‘, ‘r‘, encoding=‘utf-8‘) as f, open(‘.db.txt.swap‘, ‘w‘, encoding=‘utf-8‘) as f2:
for i in f:
user1, pwd1, money1 = i.strip().split(‘:‘)
if user1 == user_in:
money1 = int(money1)
money = int(money)
if money < money1:
money1 -= money
print(‘购买成功，金额为：{}‘.format(money))
else:
print(‘没那么多钱‘)
f2.write(‘{}:{}:{}\n‘.format(user1, pwd1, money1))
os.remove(‘db.txt‘)
os.rename(‘.db.txt.swap‘, ‘db.txt‘)
return 1
else:
print(‘请输入整数数字，傻叉‘)
@outter
def readbook1():
global money
while True:
print(‘‘‘--------------------------------
0 玄幻武侠
1 都市爱情
2 高效养猪36技
-------------------------------- ‘‘‘)
with open(‘story_class.txt‘, ‘r‘, encoding=‘utf-8‘) as f:
d = eval(f.read())
choice1 = input(‘请输入命令编号：‘).strip()
if choice1.isdigit():
if choice1 in d:
while True:
for key1, value1 in d[choice1].items():
print(‘{} {} 价格：{}‘.format(key1, value1[0], value1[1]))
choice2 = input(‘请输入命令编号：‘).strip()
if choice2.isdigit():
if choice2 in d[choice1]:
print(‘--------------------------------‘)
choice3 = input(‘是否付费：‘).strip()
print(‘--------------------------------‘)
if choice3.upper() == ‘Y‘:
money = d[choice1][choice2][1]
money_out()
break
print(‘no book‘)
else:
print(‘请输入整数数字‘)
else:
print(‘no book‘)
else:
print(‘请输入整数数字‘)
if __name__ == ‘__main__‘:
import os, time
money = 0
use_in = None
login = False
dic = {‘0‘: register, ‘1‘: money_in, ‘2‘: readbook1}
while True:
print(‘‘‘--------------------------------
0 账号注册
1 充值功能
2 阅读小说
-------------------------------- ‘‘‘)
choice = input(‘请输入命令编号：‘).strip()
if choice.isdigit():
if choice in [‘1‘, ‘2‘, ‘3‘]:
dic[choice]()
else:
print(‘没有这个编号，傻叉‘)
else:
print(‘请输入整数数字‘)
标签：bre 用户 不一致 open 命令 编号 register 确认密码 eva
原文地址：https://www.cnblogs.com/pythonwl/p/12569293.html
