车的可用捕获量

class Solution {
public:
    int numRookCaptures(vector<vector<char>>& board) {
        int res = 0;
        for(int i = 0; i < 8; i++){
            for(int j = 0; j < 8; j++){
                if(board[i][j] == ‘R‘){
                    for(int k = i-1; k >= 0; k--){
                        if(board[k][j] == ‘p‘){
                            res++;
                            break;;
                        }
                        if(board[k][j] == ‘B‘) break;
                    }
                    for(int k = i+1; k < 8; k++){
                        if(board[k][j] == ‘p‘){
                            res++;
                            break;;
                        }
                        if(board[k][j] == ‘B‘) break;
                    }
                    for(int k = j+1; k < 8; k++){
                        if(board[i][k] == ‘p‘){
                             res++; 
                             break;
                        }
                        if(board[i][k] == ‘B‘) break;
                    }
                    for(int k = j-1; k >= 0; k--){
                        if(board[i][k] == ‘p‘){
                             res++; 
                             break;
                        }
                        if(board[i][k] == ‘B‘) break;
                    }
                }
            }
        }
        return res;
    }
};