标签:else and 复数 class range lse col fun pre
def fun(num): l=[] for i in range(1,num): for j in range(1,num): for k in range(1,num): if i != j and j!= k and i != k: print(i,j,k) l.append([i,j,k]) else: continue return l,len(l) l,length=fun(5) print(l,length)
1 2 3 1 2 4 1 3 2 1 3 4 1 4 2 1 4 3 2 1 3 2 1 4 2 3 1 2 3 4 2 4 1 2 4 3 3 1 2 3 1 4 3 2 1 3 2 4 3 4 1 3 4 2 4 1 2 4 1 3 4 2 1 4 2 3 4 3 1 4 3 2 [[1, 2, 3], [1, 2, 4], [1, 3, 2], [1, 3, 4], [1, 4, 2], [1, 4, 3], [2, 1, 3], [2, 1, 4], [2, 3, 1], [2, 3, 4], [2, 4, 1], [2, 4, 3], [3, 1, 2], [3, 1, 4], [3, 2, 1], [3, 2, 4], [3, 4, 1], [3, 4, 2], [4, 1, 2], [4, 1, 3], [4, 2, 1], [4, 2, 3], [4, 3, 1], [4, 3, 2]] 24
1、2、3、4个数字,能组成多少个互不相同且无重复数字的三位数?都是多少?
标签:else and 复数 class range lse col fun pre
原文地址:https://www.cnblogs.com/pfeiliu/p/12681848.html