标签:return only pre turn ted must length strong ++
Problem:
Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2.
Note:
思路:
Solution (C++):
string addStrings(string num1, string num2) {
int m = num1.size() - 1, n = num2.size() - 1, carry = 0;
string res = "";
while (m >= 0 || n >= 0 || carry) {
long long sum = 0;
if (m >= 0) { sum += (num1[m--]-‘0‘); }
if (n >= 0) { sum += (num2[n--]-‘0‘); }
sum += carry;
carry = sum / 10;
sum %= 10;
res += to_string(sum);
}
reverse(res.begin(), res.end());
return res;
}
性能:
Runtime: 8 ms??Memory Usage: 6.9 MB
思路:
Solution (C++):
性能:
Runtime: ms??Memory Usage: MB
标签:return only pre turn ted must length strong ++
原文地址:https://www.cnblogs.com/dysjtu1995/p/12682901.html