顺序查找法

 1 def sequence_search(alist,v):
 2     for i in range(len(alist)): #i指列表的索引下标
 3         if alist[i] == v:
 4             return i 
 5     #没有找到
 6     return -1
 7 
 8 if __name__ == ‘__main__‘:
 9     alist = [4,3,5,1,223,66,99]
10     index = sequence_search(alist,99)
11     if index != -1:
12         print(‘找到该索引：‘,index)
13     else:
14         print("没有找到！")

1 找到该索引： 6