标签：col end change hang art segment class loop 相同
DATAS SEGMENT
STR1 DB ‘ABCD$‘
STR2 DB ‘ABCD$‘
len equ $-str2
;len DW str2-str1
match DB ‘EQU:‘,0DH,0AH,‘$‘
nomatch DB ‘NOEQU:‘, 0DH, 0AH, ‘$‘
change DB 0DH, 0AH, ‘$‘
E DB ‘0$‘
NTE DB ‘0$‘
DATAS ENDS
STACKS SEGMENT
;此处输入堆栈段代码
STACKS ENDS
CODES SEGMENT
ASSUME CS:CODES,DS:DATAS,SS:STACKS
START:
MOV AX,DATAS
MOV DS,AX
mov si, 0
mov cx, len
dec cx
loop1:
mov al, STR1[si]
mov ah, STR2[si]
cmp al, ah
jne l1
inc E
jmp l2
l1:
inc NTE
l2:
inc si
loop loop1
LEA dx,STR1;显示STR1和STR2两个字符串
MOV ah,09h
INT 21H
LEA dx,change
MOV ah,09h
INT 21H
LEA dx,STR2
MOV ah,09h
INT 21H
LEA dx,change
MOV ah,09h
INT 21H
LEA dx,match
MOV ah,09h
INT 21H
lea dx, E
mov ah, 09h
int 21h
LEA dx,change
MOV ah,09h
INT 21H
LEA dx,nomatch
MOV ah,09h
INT 21H
lea dx, NTE
mov ah, 09h
int 21h
MOV AH,4CH
INT 21H
CODES ENDS
END START
$代表的是当前的地址，所以当前地址减去str2的地址，就是str2的长度，同理len equ $-str1也是一样的。
标签：col end change hang art segment class loop 相同
原文地址：https://www.cnblogs.com/1-0001/p/12901897.html
