标签：ons font data subarray end cin through NPU amp
Petya and Vasya are competing with each other in a new interesting game as they always do.
At the beginning of the game Petya has to come up with an array of NN positive integers. Sum of all elements in his array should be equal to SS. Then Petya has to select an integer KK such that 0≤K≤S0≤K≤S.
In order to win, Vasya has to find a non-empty subarray in Petya‘s array such that the sum of all selected elements equals to either KK or S−KS−K. Otherwise Vasya loses.
You are given integers NN and SS. You should determine if Petya can win, considering Vasya plays optimally. If Petya can win, help him to do that.
The first line contains two integers NN and SS (1≤N≤S≤1061≤N≤S≤106) — the required length of the array and the required sum of its elements.
If Petya can win, print "YES" (without quotes) in the first line. Then print Petya‘s array in the second line. The array should contain NN positive integers with sum equal to SS. In the third line print KK. If there are many correct answers, you can print any of them.
If Petya can‘t win, print "NO" (without quotes).
You can print each letter in any register (lowercase or uppercase).
1 4
YES 4 2
3 4
NO
3 8
YES 2 1 5 4
看了有一会才搞懂题意Petya和Vasya看反了 注意 只要Vasya有可能选出一个不能满足条件的K的话就判Petya赢！
首先找出所有不可能的情况：当S/N==1的时候一定是NO，因为每个数都是正数，这样一定会出现1，因此对手只要选K=1则必输。
如果S/N>1，直接构造S/N S/N S/N ... S/N+S%N 这样只要对手选K=1则必赢。
#include <bits/stdc++.h> using namespace std; int main() { int n,s; cin>>n>>s; if(s/n>1) { cout<<"YES"<<endl; int i; for(i=1;i<=n-1;i++)cout<<s/n<<‘ ‘; cout<<s%n+s/n<<endl; cout<<1<<endl; } else cout<<"NO"<<endl; }
Codeforces Round #643 (Div. 2) D. Game With Array（构造）
标签：ons font data subarray end cin through NPU amp
原文地址：https://www.cnblogs.com/lipoicyclic/p/12902814.html
