URI获取请求参数

import java.io.UnsupportedEncodingException;
import java.net.URLDecoder;
import java.util.ArrayList;
import java.util.Date;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

public class UriSplitTest {

    public static Map<String, List<String>> getQueryParams(String url) {
        try {
            Map<String, List<String>> params = new HashMap<String, List<String>>();
            String[] urlParts = url.split("\\?");//这里分割uri成请求路径和请求参数两部分，注意这里的?不能直接作为分隔符，需要转义
            if (urlParts.length > 1) {
                String query = urlParts[1];//获取到参数字符串
                for (String param : query.split("&")) {
                    String[] pair = param.split("=");
                    String key = URLDecoder.decode(pair[0], "UTF-8");
                    String value = "";
                    if (pair.length > 1) {
                        value = URLDecoder.decode(pair[1], "UTF-8");
                    }

                    List<String> values = params.get(key);
                    if (values == null) {
                        values = new ArrayList<String>();
                        params.put(key, values);
                    }
                    values.add(value);
                }
            }

            return params;
        } catch (UnsupportedEncodingException ex) {
            throw new AssertionError(ex);
        }
    
    }
    
    public static void main(String[] args) {
        String uri = "http://120.0.0.1:8080/receiveState?timeStamp=1586937885&number=2";
        Map<String, List<String>> params = getQueryParams(uri);
        System.out.println(params.toString());//{timeStamp=[1586937885], number=[2]}
    }

}