[LeetCode]Search in Rotated Sorted Array II

标签：java   leetcode   

Follow up for "Search in Rotated Sorted Array":
What if duplicates are allowed?

Would this affect the run-time complexity? How and why?

Write a function to determine if a given target is in the array

public class Solution {
	public boolean search(int[] A, int target) {
		int l = 0;
		int r = A.length-1;
		while (l <= r) {
			int mid = (l + r) / 2;
			if (A[mid] == target) {
				return true;
			}
			if (A[mid] > A[l]) {
				if (A[mid] > target && A[l] <= target) {
					r = mid - 1;
				} else {
					l = mid + 1;
				}
			} else if(A[mid] < A[l]){
				if (A[mid] < target && A[r] >= target) {
					l = mid + 1;
				} else {
					r = mid - 1;
				}
			}else{
				return search(Arrays.copyOfRange(A, l, mid),target)||search(Arrays.copyOfRange(A, mid+1,r+1),target);
			}
		}
		return false;
	}
}

[LeetCode]Search in Rotated Sorted Array II

标签：java   leetcode   

原文地址：http://blog.csdn.net/guorudi/article/details/40895503