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反正两个人，必定至少有一个人手里的硬币价值是小于或等于所有硬币价值之和的一半的

那么我们就来扮演这个人，他的背包大小是硬币价值的一半，问，他能拿到的硬币价值的总和最大是多少？

01背包

#include<iostream>
#include<map>
#include<string>
#include<cstring>
#include<cstdio>
#include<cstdlib>
#include<cmath>
#include<queue>
#include<vector>
#include<algorithm>
using namespace std;
int a[110];
int dp[50000];
int main()
{
	int T,i,j,n,sum,m;
	cin>>T;
	while(T--)
	{
		cin>>n;
		sum=0;
		for(i=0;i<n;i++)
		{
			cin>>a[i];
			sum+=a[i];
		}
		m=sum/2;
		memset(dp,0,sizeof(dp));
		for(i=0;i<n;i++)
			for(j=m;j>=a[i];j--)
				dp[j]=max(dp[j],dp[j-a[i]]+a[i]);
		cout<<sum-2*dp[m]<<endl;
	}
	return 0;
}

Dividing coins

It‘s commonly known that the Dutch have invented copper-wire. Two Dutch men were fighting over a nickel, which was made of copper. They were both so eager to get it and the fighting was so fierce, they stretched the coin to great length and thus created copper-wire.

Not commonly known is that the fighting started, after the two Dutch tried to divide a bag with coins between the two of them. The contents of the bag appeared not to be equally divisible. The Dutch of the past couldn‘t stand the fact that a division should favour one of them and they always wanted a fair share to the very last cent. Nowadays fighting over a single cent will not be seen anymore, but being capable of making an equal division as fair as possible is something that will remain important forever...

That‘s what this whole problem is about. Not everyone is capable of seeing instantly what‘s the most fair division of a bag of coins between two persons. Your help is asked to solve this problem.

Given a bag with a maximum of 100 coins, determine the most fair division between two persons. This means that the difference between the amount each person obtains should be minimised. The value of a coin varies from 1 cent to 500 cents. It‘s not allowed to split a single coin.

Input 

• a line with a non negative integer m () indicating the number of coins in the bag
• a line with m numbers separated by one space, each number indicates the value of a coin.

Output 

Sample Input 

2
3
2 3 5
4
1 2 4 6

Sample Output 

0
1

uva 562 Dividing coins

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原文地址：http://blog.csdn.net/stl112514/article/details/40897967