标签:整数 std The etc 重要性 主程序 lse clu lower
// 计算a 和b 之间整数的平方和 // 模块化,主程序做流程控制,1个计算函数,1个输入合法函数,1个范围检测函数 #include <stdio.h> #include<stdbool.h> double sum_square(long a, long b); bool bad_limit(long begin, long end, long low, long high); long get_long(void); main() { const long MIN = -10000L; // low limit const long MAX = 10000L; // high limit long start; // lower input long stop; // upper iput double answer; // computes sum of integers //Note: printf("This progam is computer the sum of the squres of a ranger.\n"); printf("From -10000 To 10000. Enter a range to computer. \n"); printf("Input both 0 to Quit.\n"); do { printf("Input the Start: "); start = get_long(); // check and assign printf("Input the End: "); stop = get_long(); // check and assign if (bad_limit(start, stop, MIN, MAX)) // check range printf("Please Input Again.\n"); else { answer = sum_square(start, stop); //compute printf(" The sum of squares the integers from %d to %d is %g .\n", start, stop, answer); } printf("Input both 0 to Quit.\n"); } while (start != 0 || stop != 0); // input 0 to quit printf("Done, Bye bye !!!"); } //compute prog double sum_square(long a, long b) { double total = 0; long i; for (i = a;i <= b;i++) { total += (double)i * (double)i; } return total; } //get input long get_long(void) { long input; char ch; while (scanf_s("%ld", &input) != 1) { //check input is a num while ((ch = getchar()) != ‘\n‘) // ignore Enter putchar(ch); printf(" is Not an integer. \n"); printf(" Please Input a Number. \n"); } return input; } // check if or Not in the rang bool bad_limit(long begin, long end, long low, long high) { bool not_good = false; //default is good if (begin > end) { printf("%ld is Not smaller than %ld\n", begin, end); not_good = true; // not good } if (begin < low || end < low) { printf("Iput must %ld or Lager.\n", low); not_good = true; // not good } if (begin > high || end > high) { printf("Iput must %ld or Smaller.\n", high); not_good = true; // not good } return not_good; }
11 计算a 和b 之间整数的平方和,模块化思想,输入检测的重要性
标签:整数 std The etc 重要性 主程序 lse clu lower
原文地址:https://www.cnblogs.com/abel2020/p/12971509.html