标签:amp ++ 顺序 ack class 输入 push top order
输入一个矩阵,按照从外向里以顺时针的顺序依次打印出每一个数字。
输入:matrix = [[1,2,3],[4,5,6],[7,8,9]]
输出:[1,2,3,6,9,8,7,4,5]
class Solution {
public:
vector<int> spiralOrder(vector<vector<int>>& matrix) {
if(matrix.size()==0||matrix[0].size()==0) return{};
int rows = matrix.size(),columns = matrix[0].size();
vector<int> order;
int left = 0,right = columns-1,top = 0,bottom = rows - 1;
while(left<=right&&top<=bottom)
{
for(int column = left;column<=right;column++)
{
order.push_back(matrix[top][column]);
}
for(int row = top+1;row<=bottom;row++)
{
order.push_back(matrix[row][right]);
}
if(left<right&&top<bottom){
for(int column=right-1;column>left;column--)
{
order.push_back(matrix[bottom][column]);
}
for(int row = bottom;row>top;row--)
{
order.push_back(matrix[row][left]);
}
}
left++;
right--;
top++;
bottom--;
}
return order;
}
};
标签:amp ++ 顺序 ack class 输入 push top order
原文地址:https://www.cnblogs.com/just-we/p/13053037.html