标签：res return new span out integer ati class div
Given the array nums consisting of 2n elements in the form [x1,x2,...,xn,y1,y2,...,yn].
Return the array in the form [x1,y1,x2,y2,...,xn,yn].
Example 1:
Input: nums = [2,5,1,3,4,7], n = 3 Output: [2,3,5,4,1,7] Explanation: Since x1=2, x2=5, x3=1, y1=3, y2=4, y3=7 then the answer is [2,3,5,4,1,7].
Example 2:
Input: nums = [1,2,3,4,4,3,2,1], n = 4 Output: [1,4,2,3,3,2,4,1]
Example 3:
Input: nums = [1,1,2,2], n = 2 Output: [1,2,1,2]
Constraints:
1 <= n <= 500nums.length == 2n1 <= nums[i] <= 10^3class Solution { public int[] shuffle(int[] nums, int n) { int[] a1 = new int[n]; int[] a2 = new int[n]; for(int i = 0; i < 2*n; i++){ if(i < n){ a1[i] = nums[i]; } else a2[i - n] = nums[i]; } List<Integer> list = new ArrayList(); for(int i = 0; i < n; i++){ list.add(a1[i]); list.add(a2[i]); } int[] ar = new int[2*n]; for(int i = 0; i < 2*n;i++){ ar[i] = list.get(i); } return ar; } }
class Solution { public int[] shuffle(int[] nums, int n) { int[] res = new int[2*n]; for(int i = 0, j = 0; j < n; i += 2){ res[i] = nums[j]; res[i+1] = nums[j+n]; j++; } return res; } }
标签：res return new span out integer ati class div
原文地址：https://www.cnblogs.com/wentiliangkaihua/p/13070127.html
