LeetCode Reverse Integer 反转整数

 1 class Solution {
 2 public:
 3     int reverse(int x) {
 4         int e,s,num,k=0;
 5         num=x;
 6         e=0;
 7         if(x<0)
 8             num=-1*x;
 9         while( num!=0 ){
10             s=num%10;
11             e=e*10+s;
12             num=num/10;
13             k++;
14         }
15         if(x<0)
16             return -e;
17         else
18             return e;
19     }
20 };