标签:des style blog io color ar sp for strong
Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
WRONG solution:
1 /** 2 * Definition for binary tree 3 * public class TreeNode { 4 * int val; 5 * TreeNode left; 6 * TreeNode right; 7 * TreeNode(int x) { val = x; } 8 * } 9 */ 10 public class Solution { 11 public boolean isValidBST(TreeNode root) { 12 if (root==null) 13 return true; 14 15 return isValidBSTRecur(root); 16 } 17 18 public boolean isValidBSTRecur(TreeNode curNode){ 19 if (curNode.left==null&&curNode.right==null) 20 return true; 21 22 boolean leftValid=true; 23 boolean rightValid=true; 24 25 if (curNode.left!=null){ 26 if (curNode.left.val>=curNode.val) 27 return false; 28 leftValid = isValidBSTRecur(curNode.left); 29 } 30 31 if (curNode.right!=null){ 32 if (curNode.right.val<=curNode.val) 33 return false; 34 rightValid = isValidBSTRecur(curNode.right); 35 } 36 37 if (leftValid&&rightValid) 38 return true; 39 else 40 return false; 41 } 42 }
This is wrong! Because we only consider about one level up! Example:
Input: | {10,5,15,#,#,6,20} |
Output: | true |
Expected: | false |
Correct Solution:
1 /** 2 * Definition for binary tree 3 * public class TreeNode { 4 * int val; 5 * TreeNode left; 6 * TreeNode right; 7 * TreeNode(int x) { val = x; } 8 * } 9 */ 10 public class Solution { 11 public boolean isValidBST(TreeNode root) { 12 if (root==null) 13 return true; 14 15 List<Integer> queue = new ArrayList<Integer>(); 16 isValidBSTRecur(root,queue); 17 18 for (int i=1;i<queue.size();i++) 19 if (queue.get(i)<=queue.get(i-1)) 20 return false; 21 22 return true; 23 } 24 25 public void isValidBSTRecur(TreeNode curNode, List<Integer> queue){ 26 if (curNode.left==null&&curNode.right==null){ 27 queue.add(curNode.val); 28 return; 29 } 30 31 32 if (curNode.left!=null) 33 isValidBSTRecur(curNode.left,queue); 34 queue.add(curNode.val); 35 if (curNode.right!=null) 36 isValidBSTRecur(curNode.right,queue); 37 38 return; 39 } 40 }
We put nodes into a list in the preorder, then check whether the list is monotonic increasing.
标签:des style blog io color ar sp for strong
原文地址:http://www.cnblogs.com/lishiblog/p/4084378.html