pta习题：退休日期推算

标签：date   其他   ret   art   答案   add   ack   网上   输出   

DateG days2Date(int x);{//from:{1,1,1} + 100-->{1,4,11}
int Days(DateG x);// {2,,4,11}    return 465   from{1,1,1} 

#include <iostream>
using namespace std;
struct DateG{
	int yy,mm,dd;
};
char leapYear(int year);//闰年否
struct DateG _DateG(char *st);{//"1919-9-9"-->{1919,9,9}
struct DateG Add(struct DateG x,int y);//{1919,9,9}+50-->{1919,10,29}
char* Date2string(struct DateG x);//{1919,9,9}-->"1919-09-09"
 //以上为测试程序提供的测试用函数，略去不表，
//以下两函数是必须自己完成的函数 
struct DateG days2Date(int x);{//from:{1,1,1} + 100-->{1,4,11}
int Days(struct DateG x);// {2,,4,11}    return 465   from{1,1,1} 

int main(){
	char st[12];scanf("%s",st);
	struct DateG d1=_DateG(st),
	d2=Add(d1,60*365);
	printf("%s\n",Date2string(d2));	
	d2=Add(d2,-1000);
	printf("%s\n",Date2string(d2));
	d2=_DateG("2020-1-23");
	printf("%.2f\n",(Days(d2)-Days(d1))/365.0);
	return 0;
}
/* 请在这里填写答案 */

2001-1-1

[2060-12-17]
[2058-03-23]
19.07

帮其他专业的同学写网课作业，见到这道有点烦人的题目，一看网上没有现成的答案，那就自己写一份先码这把，没啥特别的技巧，典型的模拟，注意细节就好。

1. struct DateG days2Date(int x){    
2.         struct DateG Year;    
3.         Year.yy=1;    
4.         Year.mm=1;    
5.         Year.dd=1;    
6.         while(x--){    
7.             Year.dd++;    
8.             if((Year.yy%4==0&&Year.yy%100!=0)||Year.yy%400==0){//是闰年     
9.                 if((Year.mm==1||Year.mm==3||Year.mm==5||Year.mm==7||Year.mm==8||Year.mm==10||Year.mm==12)&&Year.dd>31)    
10.                 {    
11.                     Year.dd=1;    
12.                     Year.mm++;    
13.                     if(Year.mm>12){    
14.                         Year.mm=1;    
15.                         Year.yy++;    
16.                     }    
17.                 }    
18.                 else if(Year.mm==2&&Year.dd>29){//闰年二月单独讨论     
19.                     Year.dd=1;    
20.                     Year.mm++;    
21.                 }    
22.                 else if((Year.mm==4||Year.mm==6||Year.mm==9||Year.mm==11)&&Year.dd>30){    
23.                     Year.dd=1;    
24.                     Year.mm++;    
25.                 }    
26.             }    
27.             else{//非闰年     
28.                 if((Year.mm==1||Year.mm==3||Year.mm==5||Year.mm==7||Year.mm==8||Year.mm==10||Year.mm==12)&&Year.dd>31)    
29.                 {    
30.                     Year.dd=1;    
31.                     Year.mm++;    
32.                     if(Year.mm>12){    
33.                         Year.mm=1;    
34.                         Year.yy++;    
35.                     }    
36.                 }    
37.                 else if(Year.mm==2&&Year.dd>28){//二月单独讨论     
38.                     Year.dd=1;    
39.                     Year.mm++;    
40.                 }    
41.                 else if((Year.mm==2||Year.mm==4||Year.mm==6||Year.mm==9||Year.mm==11)&&Year.dd>30){    
42.                     Year.dd=1;    
43.                     Year.mm++;    
44.                 }    
45.             }    
46.         }    
47.         return Year;    
48.     }    
49.         
50.     int Days(struct DateG x){    
51.         int res=0,flag=1;    
52.         while(flag==1){    
53.             res++;    
54.             x.dd--;    
55.             if((x.yy%4==0&&x.yy%100!=0)||x.yy%400==0){//闰年    
56.                 if((x.mm==1||x.mm==3||x.mm==5||x.mm==7||x.mm==8||x.mm==10||x.mm==12)&&x.dd==0){    
57.                     if(x.mm==8||x.mm==1)    
58.                         x.dd=31;    
59.                     else if(x.mm==3)    
60.                         x.dd=29;    
61.                     else    
62.                         x.dd=30;    
63.                     x.mm--;    
64.                     if(x.mm==0){    
65.                         x.mm=12;    
66.                         x.yy--;    
67.                     }    
68.                 }    
69.                 else if((x.mm==2||x.mm==4||x.mm==6||x.mm==9||x.mm==11)&&x.dd==0){    
70.                     x.dd=31;    
71.                     x.mm--;    
72.                 }    
73.             }    
74.             else{//非闰年    
75.                 if((x.mm==1||x.mm==3||x.mm==5||x.mm==7||x.mm==8||x.mm==10||x.mm==12)&&x.dd==0){    
76.                     if(x.mm==8||x.mm==1)    
77.                         x.dd=31;    
78.                     else if(x.mm==3)    
79.                         x.dd=28;    
80.                     else    
81.                         x.dd=30;    
82.                     x.mm--;    
83.                     if(x.mm==0){    
84.                         x.mm=12;    
85.                         x.yy--;    
86.                     }    
87.                 }    
88.                 else if((x.mm==2||x.mm==4||x.mm==6||x.mm==9||x.mm==11)&&x.dd==0){    
89.                     x.dd=31;    
90.                     x.mm--;    
91.                 }    
92.             }    
93.                 
94.             if(x.yy==1&&x.mm==1&&x.dd==1)    
95.                 flag=0;    
96.         }    
97.         return res;    
98.     }  

pta习题：退休日期推算

标签：date   其他   ret   art   答案   add   ack   网上   输出   

原文地址：https://www.cnblogs.com/Simon5ei/p/13179396.html