标签:struct for 结构 main name nbsp ace == tor
给定一个整数 n,生成所有由 1 ... n 为节点所组成的 二叉搜索树 。
输入:3
输出:
[
[1,null,3,2],
[3,2,null,1],
[3,1,null,null,2],
[2,1,3],
[1,null,2,null,3]
]
解释:
以上的输出对应以下 5 种不同结构的二叉搜索树:
1 3 3 2 1
\ / / / \ 3 2 1 1 3 2
/ / \ 2 1 2 3
葱丁:
#include <iostream>
#include <vector>
using namespace std;
struct TreeNode{
int val;
TreeNode* left;
TreeNode* right;
TreeNode(int v):val(v),left(NULL),right(NULL){}
};
class Solution {
public:
vector<TreeNode*> generateTrees(int n) {
vector<TreeNode*> ret;
if(n == 0) return ret;
ret = reverse(1, n);
return ret;
}
vector<TreeNode*> reverse(int start, int end){
vector<TreeNode*> ret;
if(start>end){
ret.push_back(NULL);
}
cout<<"11"<<endl;
for(int i=start; i<=end; i++){
vector<TreeNode*> left = reverse(start, i-1);
cout<<"~~~";
vector<TreeNode*> right = reverse(i+1, end);
cout<<"---";
for(auto l : left){
for(auto r : right){
TreeNode* root = new TreeNode(i);
root->left = l;
root->right = r;
ret.push_back(root);
}
}
}
return ret;
}
void print(vector<TreeNode*> root){
TreeNode *tmp;
for(int i=0; i<root.size(); i++){
tmp = root[i];
}
}
};
int main(){
Solution s;
vector<TreeNode*> res = s.generateTrees(2);
cout<<res.size()<<endl;
cout<<res[0]->val<<" "<<res[0]->left<<" "<<res[0]->right->val<<endl;
return 0;
}
标签:struct for 结构 main name nbsp ace == tor
原文地址:https://www.cnblogs.com/bailuoxi/p/13199268.html