标签:from levels cooper space namespace led bit cpp rom
There is a game called "I Wanna Be the Guy", consisting of n levels. Little X and his friend Little Y are addicted to the game. Each of them wants to pass the whole game.
Little X can pass only p levels of the game. And Little Y can pass only q levels of the game. You are given the indices of levels Little X can pass and the indices of levels Little Y can pass. Will Little X and Little Y pass the whole game, if they cooperate each other?
Input
The first line contains a single integer n (1?≤??n?≤?100).
The next line contains an integer p (0?≤?p?≤?n) at first, then follows p distinct integers a 1,?a 2,?...,?a p (1?≤?a i?≤?n). These integers denote the indices of levels Little X can pass. The next line contains the levels Little Y can pass in the same format. It‘s assumed that levels are numbered from 1 to n.
Output
If they can pass all the levels, print "I become the guy.". If it‘s impossible, print "Oh, my keyboard!" (without the quotes).
Examples
input
4
3 1 2 3
2 2 4
output
I become the guy.
input
4
3 1 2 3
2 2 3
output
Oh, my keyboard!
Note
In the first sample, Little X can pass levels [1 2 3], and Little Y can pass level [2 4], so they can pass all the levels both.
In the second sample, no one can pass level 4.
1 - n 如果全部出现了则输出 I become the guy.
不然输出 Oh, my keyboard!
#include<bits/stdc++.h>
using namespace std;
int n, _size, input; set<int>ans;
int main() {
cin >> n; for (int i = 2; i--;)for (cin >> _size; _size--;)cin >> input, ans.insert(input);
cout << (n == ans.size() ? "I become the guy.\n" : "Oh, my keyboard!\n");
}
CodeForces - 469A I Wanna Be the Guy
标签:from levels cooper space namespace led bit cpp rom
原文地址:https://www.cnblogs.com/RioTian/p/13199965.html