【LeetCode】【Linked List】Convert binary number in a linked list to integer

标签：not   strong   upload   ima   lis   ssi   loading   ber   png   

题目：

给定head(头节点)，它是单链表的参考节点。 链表中每个节点的值为0或1。链表中包含数字的二进制表示形式。返回链接列表中数字的十进制值。

Example 1:

Input: head = [1,0,1]
Output: 5
Explanation: (101) in base 2 = (5) in base 10

Example 2:

Input: head = [0]
Output: 0

Example 3:

Input: head = [1]
Output: 1

Example 4:

Input: head = [1,0,0,1,0,0,1,1,1,0,0,0,0,0,0]
Output: 18880

Example 5:

Input: head = [0,0]
Output: 0

Constraints:

• The Linked List is not empty.
• Number of nodes will not exceed 30.
• Each node‘s value is either 0 or 1.

【解法】

图源自@YaoFrankie

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, val=0, next=None):
#         self.val = val
#         self.next = next
class Solution:
    def getDecimalValue(self, head: ListNode) -> int:
        ans = 0
        while head:
            ans = (ans << 1) | head.val
            head = head.next
        return ans

class Solution:
    def getDecimalValue(self, head: ListNode) -> int:
        answer = 0
        while head: 
            answer = 2*answer + head.val 
            head = head.next 
        return answer

【LeetCode】【Linked List】Convert binary number in a linked list to integer

标签：not   strong   upload   ima   lis   ssi   loading   ber   png   

原文地址：https://www.cnblogs.com/jialinliu/p/13217383.html