标签:i++ 出现 tps ++ numbers fan 编写 编程 iba
编写程序,读取在1到100 之间的整数,然后计算每个数出现的次数。假定输入是以0 结束的。
下面是这个程序的一个运行示例:
Write a program that reads the integers between 1and 100 and counts the occurrences of each. Assume the input ends with 0.Note that if a number occurs more than one time, the plural word “times” is used
in the output.
Enter the integers between 1 and 100: 2 5 6 5 4 3 23 43 2 0
2 occurs 2 times
3 occurs 1 time
4 occurs 1 time
5 occurs 2 times
6 occurs 1 time
23 occurs 1 time
43 occurs 1 time
下面是参考答案代码:
// https://cn.fankuiba.com
import java.util.Scanner;
public class Ans7_3_page236 {
public static void main(String[] args) {
int[] number = new int [101];
Scanner input = new Scanner(System.in);
int num;
System.out.print("Enter the integers between 1 and 100: ");
do {
num = input.nextInt();
number[num] = number[num] + 1;
}
while (num != 0);
for (int i = 1; i < number.length; i++) {
if (number[i] == 1) {
System.out.println(i + " occurs " + number[i] + " time");
}else if (number[i] > 1)
System.out.println(i + " occurs " + number[i] + " times");
}
}
}
适用Java语言程序设计与数据结构(基础篇)(原书第11版)Java语言程序设计(基础篇)(原书第10/11版)
发布在博客:(https://cn.fankuiba.com)
第七章第三题(计算数字的出现次数)(Count occurrence of numbers) - 编程练习题答案
标签:i++ 出现 tps ++ numbers fan 编写 编程 iba
原文地址:https://www.cnblogs.com/in2013/p/13232508.html