标签:treenode info desc add nbsp empty return int pop
BFS 解法:
private final void addRow(Stack<TreeNode> stack, int v) { while (!stack.empty()) { TreeNode node = stack.pop(); TreeNode newNodeLeft = new TreeNode(v); TreeNode newNodeRight = new TreeNode(v); newNodeLeft.left = node.left; newNodeRight.right = node.right; node.left = newNodeLeft; node.right = newNodeRight; } } /** * @Author Niuxy * @Date 2020/7/17 * @Description BFS */ public final TreeNode addOneRow(TreeNode root, int v, int d) { if (d == 1) { TreeNode newRoot = new TreeNode(root.val); newRoot.left = root.left; newRoot.right = root.right; root.left = newRoot; root.right = null; root.val = v; return root; } Stack<TreeNode> stack1 = new Stack<TreeNode>(); Stack<TreeNode> stack2 = new Stack<TreeNode>(); stack1.push(root); int length = 1; while (!(stack1.empty() && stack1.empty())) { while (!stack1.empty()) { boolean isInsert = isInsert(stack1, stack2, d, v, length, root); if (isInsert) { return root; } } length++; while (!stack2.empty()) { boolean isInsert = isInsert(stack2, stack1, d, v, length, root); if (isInsert) { return root; } } length++; } return root; } private final boolean isInsert(Stack<TreeNode> stack1, Stack<TreeNode> stack2, int d, int v, int length, TreeNode root) { if (length == d - 1) { addRow(stack1, v); return true; } TreeNode node = stack1.pop(); if (node.left != null) { stack2.push(node.left); } if (node.right != null) { stack2.push(node.right); } return false; }
DFS解法:
public final TreeNode addOneRowDFS(TreeNode root, int v, int d) { if (d == 1) { TreeNode newRoot = new TreeNode(root.val); newRoot.left = root.left; newRoot.right = root.right; root.left = newRoot; root.right = null; root.val = v; return root; } Stack<TreeNode> stack = new Stack<TreeNode>(); dfs(root, v, d, stack); addRow(stack, v); return root; } public final void dfs(TreeNode node, int v, int d, Stack<TreeNode> stack) { if (node == null) { return; } if (d == 2) { stack.push(node); return; } dfs(node.left, v, d - 1, stack); dfs(node.right, v, d - 1, stack); } private final void addRow(Stack<TreeNode> stack, int v) { while (!stack.empty()) { TreeNode node = stack.pop(); TreeNode newNodeLeft = new TreeNode(v); TreeNode newNodeRight = new TreeNode(v); newNodeLeft.left = node.left; newNodeRight.right = node.right; node.left = newNodeLeft; node.right = newNodeRight; } }
Leetcode 623 在二叉树中增加一行 BFS与DFS
标签:treenode info desc add nbsp empty return int pop
原文地址:https://www.cnblogs.com/niuyourou/p/13329190.html