标签:vat length order ext evel pack parent ever and
package LeetCode_301 import java.util.* import kotlin.collections.ArrayList import kotlin.collections.HashSet /** * 301. Remove Invalid Parentheses * https://leetcode.com/problems/remove-invalid-parentheses/description/ * * Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other than the parentheses ( and ). Example 1: Input: "()())()" Output: ["()()()", "(())()"] Example 2: Input: "(a)())()" Output: ["(a)()()", "(a())()"] Example 3: Input: ")(" Output: [""] * */ class Solution { /* * solution: BFS, Time complexity:O(2^n), Space complexity:O(2^n) * */ fun removeInvalidParentheses(s: String): List<String> { val result = ArrayList<String>() val visited = HashSet<String>() val queue = LinkedList<String>() queue.offer(s) while (queue.isNotEmpty()) { val cur = queue.poll() if (visited.contains(cur)) { continue } visited.add(cur) if (isValidParenthese(cur)) { result.add(cur) } //if found in this level, no need to loop again if (result.size != 0) { continue } for (i in cur.indices) { if (cur[i] == ‘(‘ || cur[i] == ‘)‘) { /* check every children * for example:()())(), * children: remove first ‘(‘=>)())() * remove the second:‘)‘=>(())() * */ val children = cur.substring(0, i) + cur.substring(i + 1, cur.length) queue.offer(children) } } } //println(result) return result } private fun isValidParenthese(s: String): Boolean { var count = 0 for (c in s) { if (c == ‘(‘) { count++ } else if (c == ‘)‘) { count-- } if (count < 0) { return false } } return count == 0 } }
301. Remove Invalid Parentheses
标签:vat length order ext evel pack parent ever and
原文地址:https://www.cnblogs.com/johnnyzhao/p/13364038.html