标签:namespace amp 二分 art c代码 ++ task medium cout
题目相关链接传送门:
1.https://blog.csdn.net/justidle/article/details/104593327?utm_medium=distribute.pc_relevant.none-task-blog-baidujs-5&spm=1001.2101.3001.4242
2.https://vjudge.net/contest/378940#problem/C
我的AC代码:
#include<bits/stdc++.h>
using namespace std;
int lower_bound(int a[],int left,int right,int x)
{
while(left<=right)
{
int mid=(left+right)/2;
if(a[mid]>=x) right=mid-1;
else left=mid+1;
}
return left;
}
int main()
{
int n,m,i;
cin>>n>>m;
int a[n];
for(i=0;i<n;i++) cin>>a[i];
sort(a,a+n);
for(i=0;i<m;i++)
{
int x;
cin>>x;
if(x<a[0]) cout<<a[0]<<endl;
else if(x>a[n-1]) cout<<"-1\n";
else
{
int pos=lower_bound(a,0,n-1,x);
cout<<a[pos]<<endl;
}
}
}
标签:namespace amp 二分 art c代码 ++ task medium cout
原文地址:https://www.cnblogs.com/dragondragon/p/13380201.html