标签：dia test app print std des sum base nbsp
7
3 8
8 1 0
2 7 4 4
4 5 2 6 5
（Figure 1)
Figure 1 shows a number triangle. Write a program that calculates the highest sum of numbers passed
on a route that starts at the top and ends somewhere on the base. Each step can go either diagonally
down to the left or diagonally down to the right.
给出一个数字三角形，你从[1,1]开始出发，走到最后一行。每次站在一个点上时，可以向下走，或者向右下走。
将经过的数字加起来，希望其和最大。
The first line contains one integer N: the number of rows in the triangle.
The following N lines describe the data of the triangle.
The number of rows in the triangle is > 1 but <= 100.
The numbers in the triangle, all integers, are between 0 and 99.
Your program is to write to standard output. The highest sum is written as an integer.
5 7 3 8 8 1 0 2 7 4 4 4 5 2 6 5
1 #include<bits/stdc++.h> 2 using namespace std; 3 int a[1001][1001],n,f[10001][1001],ans=-1; 4 int main() { 5 scanf("%d",&n); 6 for(int i=1; i<=n; i++) 7 for(int j=1; j<=i; j++) 8 scanf("%d",&a[i][j]); 9 memset(f,-1,sizeof(f)); 10 f[1][1]=a[1][1]; 11 for(int i=2; i<=n; i++) 12 for(int j=1; j<=i; j++) 13 f[i][j]=max(f[i-1][j-1],f[i-1][j])+a[i][j]; 14 for(int i=1; i<=n; i++) 15 ans=max(ans,f[n][i]); 16 printf("%d\n",ans); 17 return 0; 18 }
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标签：dia test app print std des sum base nbsp
原文地址：https://www.cnblogs.com/sbwll/p/13380950.html
