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字典树-HDOJ-1671

时间:2014-11-11 16:37:02      阅读:208      评论:0      收藏:0      [点我收藏+]

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Phone List

Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 11016    Accepted Submission(s): 3805


Problem Description
Given a list of phone numbers, determine if it is consistent in the sense that no number is the prefix of another. Let’s say the phone catalogue listed these numbers:
1. Emergency 911
2. Alice 97 625 999
3. Bob 91 12 54 26
In this case, it’s not possible to call Bob, because the central would direct your call to the emergency line as soon as you had dialled the first three digits of Bob’s phone number. So this list would not be consistent.
 

Input
The first line of input gives a single integer, 1 <= t <= 40, the number of test cases. Each test case starts with n, the number of phone numbers, on a separate line, 1 <= n <= 10000. Then follows n lines with one unique phone number on each line. A phone number is a sequence of at most ten digits.
 

Output
For each test case, output “YES” if the list is consistent, or “NO” otherwise.
 

Sample Input
2 3 911 97625999 91125426 5 113 12340 123440 12345 98346
 

Sample Output
NO YES
 

Source


bubuko.com,布布扣题目大意:给定n个数字序列,判断是否存在两个序列a、b,满足a是b的前缀。若存在,输出"NO",囧~

bubuko.com,布布扣解答:必须用scanf 、必须GC、TrieNode的子树节点控制到10个,省空间.



字典树-HDOJ-1671

标签:des   style   blog   http   io   color   ar   os   java   

原文地址:http://blog.csdn.net/chuchus/article/details/41012303

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