标签:shutdown form blocking pre 导致 rest rtp adf actor
LongAccumulator.reset方法并不能重置重置LongAccumulator的identity:初始值正确,使其恢复原来的初始值。当初始值为0是不会发生这个问题,而当我们设置初始值如1时,就会导致后续的计算操作增加了5份初始值,目前猜测原因是因为代码中LongAccumulator在并发量比较大的情况下,操作数据的时候,相当于把这个数字分成了很多份数字 ,而初始化的时候也是初始化了多份数据,导致初始值叠加了多份。不知道这是个bug么?待解惑。
在此记录下来希望有遇到这种情况的同学注意。解决方法便是要么初始值identity=0不会有这种问题;或者有需要使用reset方法重置的改为重新创建个LongAccumulator处理。
源码:
public void reset() {
Cell[] as = cells; Cell a;
base = identity;
if (as != null) {
for (int i = 0; i < as.length; ++i) {
if ((a = as[i]) != null)
//对多个cell进行初始值赋值导致后面计算叠加了多份初始值
a.value = identity;
}
}
}
示例:
public class LongAccumulatorTest {
//设置初始值为1查看输出结果
private static volatile LongAccumulator count = new LongAccumulator((x, y) -> x + y, 1);
public static void main(String[] args) throws InterruptedException {
for (int i = 0; i < 5; i++) {
count.reset();
averageTest();
}
}
public static void averageTest() throws InterruptedException {
long t1 = System.currentTimeMillis();
//自定义包含策略
ThreadPoolExecutor executor = new ThreadPoolExecutor(50, 50, 60,
TimeUnit.SECONDS, new LinkedBlockingQueue<>(5),
new DemoThreadFactory("订单创建组"), new ThreadPoolExecutor.AbortPolicy());
CountDownLatch latch = new CountDownLatch(50);
for (int i = 0; i < 50; i++) {
executor.execute(() -> {
try {
for (int j = 0; j < 1000000; j++) {
count.accumulate(1);
}
} finally {
latch.countDown();
}
});
}
latch.await();
long t2 = System.currentTimeMillis();
System.out.println(String.format("结果:%s,耗时(ms):%s", count.longValue(), (t2 - t1)));
executor.shutdown();
}
}
输出:这时候你会发现只有第一次计算是正确的,只要使用了rest方法重置就会导致这个错误。
结果:50000001,耗时(ms):185
结果:50000005,耗时(ms):143
结果:50000005,耗时(ms):139
结果:50000005,耗时(ms):162
结果:50000005,耗时(ms):142
LongAccumulator类的BUG——reset方法并不能保证初始值正确赋值
标签:shutdown form blocking pre 导致 rest rtp adf actor
原文地址:https://www.cnblogs.com/castamere/p/13650793.html