标签:html mamicode bsp ati 思路 字符串 substr png param
思路参考:最长公共子序列
public class Solution { /** * longest common substring * @param str1 string字符串 the string * @param str2 string字符串 the string * @return string字符串 */ public static String LCS(String str1, String str2) { if (str1 == null || str2 == null || str1.equals("") || str2.equals("")) { return ""; } str1 = " " + str1; str2 = " " + str2; char[] chars1 = str1.toCharArray(); char[] chars2 = str2.toCharArray(); int maxlen = 0; int maxi=0; int[][] dp = new int[str1.length()][str2.length()]; for (int i = 1; i < str1.length(); i++) { for (int j = 1; j < str2.length(); j++) { if (chars1[i] == chars2[j]) { if (chars1[i - 1] != chars2[j - 1]) { dp[i][j] = 1; } else { dp[i][j] = dp[i - 1][j - 1] + 1; } } else { dp[i][j] = Math.max(dp[i-1][j],dp[i][j-1]); } if (maxlen<dp[i][j]){ maxlen = dp[i][j]; maxi = i; } } } if (maxlen == 0){ return "-1"; } return str1.substring(maxi-maxlen+1,maxi+1); } }
标签:html mamicode bsp ati 思路 字符串 substr png param
原文地址:https://www.cnblogs.com/Adam-Ye/p/13778662.html