代码练习，求0-100之内可以被3整除的数

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    int main()
    {
    int i = 0;
    int count = 0;
    for (i = 1; i <= 100; i++)
    {
        if (i % 3 == 0)
        {
            printf("%d ", i);
                count++;
        }
    }
    printf("\nconut=%d\n", count);
    return 0;
}

运行结果
![](https://s4.51cto.com/images/blog/202010/31/d9decfe0174eb8081759f4dd2dacef37.png?x-oss-process=image/watermark,size_16,text_QDUxQ1RP5Y2a5a6i,color_FFFFFF,t_100,g_se,x_10,y_10,shadow_90,type_ZmFuZ3poZW5naGVpdGk=)
解法二
```
int main()

{
int a = 1;
int count = 0;
while (a <= 100)
{
if (a % 3 == 0)
{
printf("%d ", a);
a++;
count++;
}
else
a++;
}
printf("\nconut=%d\n", count);
return 0;
}

运行结果
![](https://s4.51cto.com/images/blog/202010/31/6c3aed517bd16348d905ae33db2590e3.png?x-oss-process=image/watermark,size_16,text_QDUxQ1RP5Y2a5a6i,color_FFFFFF,t_100,g_se,x_10,y_10,shadow_90,type_ZmFuZ3poZW5naGVpdGk=)

代码练习，求0-100之内可以被3整除的数

标签：sha   oss   log   images   练习   ado   pre   解法   proc   

原文地址：https://blog.51cto.com/14950896/2545747