输入一个正数s，打印出所有和为s的连续正数序列（至少含有两个数）。例如输入15，由于1+2+3+4+5=4+5+6=7+8=15，所以结果打印出3个连续序列1～5、4～6和7～8。

void findContinuousSequence(int sum){
    if(sum < 3){
        return;
    }
    int small = 1;
    int big = 2;
    int mid = (1 + sum) >> 1;
    while (small < mid && big <= mid){
        int curSum = 0;
        for (int i = small; i <= big; ++i) {
            curSum += i;
        }
        if(curSum == sum){
            for (int i = small; i <= big; ++i) {
                if(i == big){
                    cout<<i<<"=";
                } else{
                    cout<<i<<"+";
                }
            }
            cout<<sum<<endl;
            big++;
        }
        else if(curSum < sum){// 序列小于指定值，big++
            big++;
        } else{
            small++;
        }
    }
}