标签:位置 输出 oat break can ati load enter ret
任务一
#include<stdio.h> #include<math.h> int main(){ float a, b, c, x1, x2; float delta, real, imag; printf("Enter a, b, c: "); while(scanf("%f%f%f", &a, &b, &c)!=EOF){ if(a == 0) printf("not quadratic equation.\n\n"); else{ delta = b*b - 4*a*c; if(delta >= 0){ x1 = (-b + sqrt(delta)) / (2*a); x2 = (-b - sqrt(delta)) / (2*a); printf("x1 = %.2f, x2 = %.2f\n\n", x1, x2); } else{ real = -b / (2*a); imag = sqrt(-delta) / (2*a); printf("x1 = %.2f + %.2fi, x2 = %.2f - %.2fi\n\n", real, imag, real, imag); } } printf("Enter a, b, c: "); } return 0; }
任务二
#include<stdio.h> #include<stdlib.h> #include<time.h> #define N 5 int main(){ int x, n; srand(time(0)); n = 0; do{ n++; x = rand()%10; printf("%3d", x); }while(n < N); printf("\n"); return 0; }
任务三
#include<stdio.h> #include<math.h> int main() { int N, n; int count = 0; for(N = 101; N <= 200; N++) { for(n = 2; n <= sqrt(N); n++) { if(N%n == 0) break; } if(n > sqrt(N)) { printf("%4d", N); count++;//统计素数的个数 if(count%5 == 0)// 每行输出五个数字 printf("\n"); } } printf("\n"); printf("101~200之间有%d个素数\n", count); return 0; }
任务四
#include<stdio.h> #include<math.h> int main() { long int s; printf("Enter a number:"); while(scanf("%ld", &s) != EOF) { int i = 1; long int k = 0; int m = 0; printf("new number is:"); while(s) //当s不为0时,表达式为真,执行循环 { i = s%10; //取s最后一位 s /= 10; if(i%2 == 0) continue; //跳过偶数 k += pow(10,m)*i; m++; //通过计算循环的次数来确定奇数的位置 } printf("%ld", k); printf("\n\n"); printf("Enter a number:"); } return 0; }
任务五
#include<stdio.h> #include<math.h> int main(){ int n, i; int k; double s; printf("Enter n(1~10): "); while(scanf("%d", &n) != EOF) { k = 1; s = 0; for(i = 1; i <= n; i++) { k *= i; s += 1.0*pow(-1,i-1)/k; } printf("n = %d, s = %lf\n\n", n, s); printf("Enter n(1~10): "); } return 0; }
任务六
#include<stdio.h> #include<stdlib.h> #include<time.h> int main() { int x, i; int date; srand(time(0)); x = rand()%31; printf("猜猜2020年12月哪一天会是你的lucky day\n\n"); printf("开始喽,你有三次机会,猜吧(1~31):"); for(i = 1; i <= 3; i++) { scanf("%d", &date); printf("\n"); if(x == date) { printf("恭喜你猜对了!\n"); break; } else if(x > date) printf("你猜的日期早了,lucky day还没到呢\n\n"); else printf("你猜的日期晚了,lucky day悄悄溜到前面啦\n\n"); if(i != 3) printf("再猜(1~31):"); } if(i == 4) printf("次数用完啦。偷偷告诉你,你的lucky day是%d号\n", x); return 0; }
标签:位置 输出 oat break can ati load enter ret
原文地址:https://www.cnblogs.com/wjxing/p/13997579.html