标签:problem splay inf ccf 图片 out close between typedef
https://codeforces.ml/problemset/problem/1343/D
差分:
对于每一对max+min=sum,当sum等于以下区间的值时需要改变的次数;
[2,min]+=2;
[max+k+1,2*k]+=2;
[min+1,max+k]+=1; [max+min,max+min]-=1;
#include <bits/stdc++.h> using namespace std; const int MAXN=1e6+5; typedef long long ll; const int mod=1e9+7; typedef unsigned long long ull; //typedef __int128 LL; const double eps=10e-8; const double pi=acos(-1.0); #define between(x,a,b)(a<=x && x<=b) const int inf=0x3f3f3f3f; const long long INF=0x3f3f3f3f3f3f3f3f; typedef pair<ll,ll> pII; typedef pair<int,int> pii; typedef pair<int,ll> piI; int a[MAXN]; int f[MAXN]; int main() { #ifndef ONLINE_JUDGE freopen("1.in", "r", stdin); freopen("debug.out", "w", stdout); #endif int t; scanf("%d",&t); while(t--) { int n,k; scanf("%d%d",&n,&k); for(int i=1;i<=2*k;i++)f[i]=0; for(int i=1;i<=n;i++)scanf("%d",&a[i]); for(int i=1;i<=n/2;i++) { int maxn=max(a[i],a[n-i+1]); int minn=min(a[i],a[n-i+1]); f[2]+=2;f[minn+1]-=2; f[maxn+k+1]+=2;f[2*k+1]-=2; f[minn+1]+=1;f[maxn+k+1]-=1; f[maxn+minn]--;f[maxn+minn+1]++; } int ans=inf; for(int i=2;i<=2*k;i++) { f[i]=f[i-1]+f[i]; ans=min(f[i],ans); } printf("%d\n",ans); } return 0; }
D. Constant Palindrome Sum 差分+思维
标签:problem splay inf ccf 图片 out close between typedef
原文地址:https://www.cnblogs.com/MZRONG/p/14136146.html