消除装饰器对原函数的属性影响

import os
def decor(func):
    def with_decor(*args, **kwargs):　　#这里内部嵌套函数使原函数参数能顺利传递
        func(*args, **kwargs)　　#func_A 会在这里被调用
        a = args
        print(a)
    print(‘call decor‘)
    return with_decor

@decor
def func_A(*args, **kwargs):
    print(‘call A‘)
    
func_A(1,2,3)
os.system("pause")

import os
from functools import wraps
def decor(func):
    @wraps(func)
    def with_decor(*args, **kwargs):
        return func(*args, **kwargs)
    return with_decor

@decor
def func_A(*args, **kwargs):
    print(‘call A‘)
    
func_A(1,2,3)
print(func_A.__name__)
os.system("pause")