标签:mod join file_path art get str 注释 readlines continue
import os
file_types = [‘py‘,
‘html‘,
‘css‘,
‘js‘,
]
def count_code_nums(file):
"""获取单个文件的行数
"""
with open(file, mode=‘rb‘) as f:
return len(f.readlines())
def count_code_nums_pro(file):
"""获取单个文件的行数-去注解,utf8代码
"""
with open(file, mode =‘r‘,encoding=‘utf-8‘) as data:
count, flag = 0, 0 # 代码行数, 开头注解标示
begin = (‘"""‘, "‘‘‘")
for line in data:
line2 = line.strip()
# 以#开头
if line2.startswith(‘#‘):
continue
# 以(‘"""‘, "‘‘‘") 开头
elif line2.startswith(begin):
# (‘"""‘, "‘‘‘") 开头 ,且当前行(‘"""‘, "‘‘‘")结束 ,跳过计算
if line2.endswith(begin) and len(line2) > 3:
flag = 0
continue
# (‘"""‘, "‘‘‘") 开头 ,没有(‘"""‘, "‘‘‘")结束,标志没有置上
elif flag == 0:
flag = 1
# (‘"""‘, "‘‘‘") 开头 ,没有(‘"""‘, "‘‘‘")结束,标志置上(注解内的注解),跳过计算
else:
flag = 0
continue
# 不是#和(‘"""‘, "‘‘‘") 开头 ;
# 以(‘"""‘, "‘‘‘")结束且标志置上,注解最后一行
elif flag == 1 and line2.endswith(begin):
flag = 0
continue
else:
# 不用处理,flag == 1 的中间注释行
pass
# 标志没有置上的有效行才计数
if flag == 0 and line2:
count += 1
return count
def get_all_file_in_paths(path, end_with=[‘py‘,‘html‘,‘css‘,‘js‘]):
"""获取给定路径下所有子文件路径
"""
res = []
for r_path in os.walk(path):
for f_name in r_path[2]:
str_list = f_name.rsplit(‘.‘, maxsplit=1)
if end_with:
if str_list.pop() in end_with:
# print(f_name)
res.append(os.path.join(r_path[0], f_name))
else:
res.append(os.path.join(r_path[0], f_name))
return res
def file_path(path, pro_mode=True, file_type=file_types):
total_line = 0
file_list = get_all_file_in_paths(path, end_with=file_type)
for file in file_list:
if pro_mode:
line_num = count_code_nums_pro(file)
else:
line_num = count_code_nums(file)
total_line += line_num
return total_line
if __name__ == ‘__main__‘:
dir_path = r‘C:\Python\site-packages\robot‘
lines = file_path(dir_path, pro_mode=False,file_type=None ) # 计算注解,所有文件类型 # 64063
# lines = file_path(dir_path, pro_mode=False, ) # 计算注解,文件类型 [‘py‘,‘html‘,‘css‘,‘js‘] # 46128
# lines = file_path(dir_path, pro_mode=True) # 去掉注解,文件类型 [‘py‘,‘html‘,‘css‘,‘js‘] # 26409
print(‘robot is:‘, lines)
标签:mod join file_path art get str 注释 readlines continue
原文地址:https://www.cnblogs.com/amize/p/14584865.html