标签:namespace ++ 主席树 sign amp roo add lse nod
#include <iostream>
#include <algorithm>
#include <cstdio>
using namespace std;
const int N = 2e5 * 20;
int a[N], b[N], root[N];
struct President_Tree {
int idx;
struct node {
int l, r, data;
}tr[N];
inline void add(int &p, int q, int l, int r, int x) {
p = ++idx;tr[p] = tr[q];tr[p].data ++ ;
if (l == r)return;
int mid = l + r >> 1;
if (x <= mid)add(tr[p].l, tr[q].l, l, mid, x);
else add(tr[p].r, tr[q].r, mid + 1, r, x);
}
inline int ask(int p, int q, int l, int r, int k) {
if (l == r)return l;
int cnt = tr[tr[p].l].data - tr[tr[q].l].data;
int mid = l + r >> 1;
if (k <= cnt)return ask(tr[p].l, tr[q].l, l, mid, k);
else return ask(tr[p].r, tr[q].r, mid + 1, r, k - cnt);
}
}T;
signed main() {
int n, m;
while (~scanf("%d%d", &n, &m)) {
T.idx = 0;
for (int i = 1; i <= n; i ++)scanf("%d", &a[i]),b[i] = a[i];
sort(b + 1, b + 1 + n);
int nn = unique(b + 1, b + 1 + n)-b-1;
for (int i = 1; i <= n; i ++)T.add(root[i], root[i-1], 1, nn, lower_bound(b + 1, b + 1 + nn, a[i])-b );
while (m--) {
int l, r, k;scanf("%d%d%d", &l, &r, &k);
printf("%d\n", b[T.ask(root[r], root[l-1], 1, nn, k)]);
}
}
}
标签:namespace ++ 主席树 sign amp roo add lse nod
原文地址:https://www.cnblogs.com/Xiao-yan/p/14706621.html