【每日一题】403. 青蛙过河

标签：return   com   problem   targe   can   amp   binary   bool   ble   

https://leetcode-cn.com/problems/frog-jump/

思路：
待补充

class Solution {
    private Boolean[][] rec;

    public boolean canCross(int[] stones) {
        int n = stones.length;
        rec = new Boolean[n][n];
        return dfs(stones, 0, 0);
    }

    private boolean dfs(int[] stones, int i, int lastDis) {
        if (i == stones.length - 1) {
            return true;
        }
        if (rec[i][lastDis] != null) {
            return rec[i][lastDis];
        }

        for (int curDis = lastDis - 1; curDis <= lastDis + 1; curDis++) {
            if (curDis > 0) {
                int j = Arrays.binarySearch(stones, i + 1, stones.length, curDis + stones[i]);
                if (j >= 0 && dfs(stones, j, curDis)) {
                    return rec[i][lastDis] = true;
                }
            }
        }
        return rec[i][lastDis] = false;
    }
}

【每日一题】403. 青蛙过河

标签：return   com   problem   targe   can   amp   binary   bool   ble   

原文地址：https://www.cnblogs.com/realzhaijiayu/p/14720285.html