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744. Find Smallest Letter Greater Than Target

时间:2021-06-17 17:13:05      阅读:0      评论:0      收藏:0      [点我收藏+]

标签:tle   while   distinct   const   exit   must   contains   rgb   tin   

Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You must write an algorithm with O(log n) runtime complexity.

 

Example 1:

Input: nums = [1,3,5,6], target = 5
Output: 2

Example 2:

Input: nums = [1,3,5,6], target = 2
Output: 1

Example 3:

Input: nums = [1,3,5,6], target = 7
Output: 4

Example 4:

Input: nums = [1,3,5,6], target = 0
Output: 0

Example 5:

Input: nums = [1], target = 0
Output: 0

 

Constraints:

  • 1 <= nums.length <= 104
  • -104 <= nums[i] <= 104
  • nums contains distinct values sorted in ascending order.
  • -104 <= target <= 104
class Solution {
    public char nextGreatestLetter(char[] letters, char target) {
        //if (letters[0] > target) return letters[0];
        if (letters[letters.length - 1] <= target) return letters[0];
        int l = 0, r = letters.length - 1;
        while(l <= r) {
            int m = l + (r - l) / 2;
            if(letters[m] > target) r = m - 1;
            else l = m + 1;
        }
        return letters[l];
    }
}

 

744. Find Smallest Letter Greater Than Target

标签:tle   while   distinct   const   exit   must   contains   rgb   tin   

原文地址:https://www.cnblogs.com/wentiliangkaihua/p/14892956.html

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