标签:style blog io color ar os sp for strong
【问题描述】
Fred想在一块地上买房子,但那块地每年都会收缩50m2,给定一个房子坐标,输出几年后房子会被侵蚀入海中。
【思路分析】
该题也算是简单题,只要读懂题目就没什么问题了。
唯一要注意的地方是每年会收缩50m2,如果在上一年的基础上算收缩50m2会呈一个半环形,比较麻烦。索性直接计算出从开始到某一年收缩的总量,这时只要求半圆的半径就可解决。
【附:完整代码】
/* * POJ-1005 I Think I Need a Houseboat */ #include <iostream> #include <cmath> using namespace std; #define PI 3.1415926 int main() { int n, i = 1; cin>>n; while (i <= n) { double x, y; cin>>x>>y; double distance = sqrt(x*x + y*y); int years; for (years = 1; true; years++) { double shrinkingArea = years * 50.0; double shrinkingRadius = sqrt(2 * shrinkingArea / PI); if (shrinkingRadius >= distance) break; } cout<<"Property "<<i++<<": This property will begin eroding in year "<<years<<"."<<endl; } cout<<"END OF OUTPUT."<<endl; return 0; }
POJ-1005 I Think I Need a Houseboat
标签:style blog io color ar os sp for strong
原文地址:http://www.cnblogs.com/xcwu/p/4099480.html