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leetcode [64] merge tow sorted lists

时间:2014-11-15 18:30:36      阅读:169      评论:0      收藏:0      [点我收藏+]

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之前忘记记录这题了,现在补上。

合并两个有序的list,要求是:

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.

不知道我如下做是不是符合题目要求呢。

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
ListNode *mergeTwoLists(ListNode *l1, ListNode *l2)
{
    if (l1 == NULL) return l2;
    if (l2 == NULL) return l1;
    ListNode *tmp = new ListNode(0);
    ListNode *head = tmp;
    while(l1 && l2)
    {
        if (l1 -> val <= l2 -> val)
        {
            tmp -> next = l1;
            tmp = l1;
            l1 = l1 -> next;
        }
        else
        {
            tmp -> next = l2;
            tmp = l2;
            l2 = l2 -> next;
        }
    }
    if (l1)
    {
        tmp -> next = l1;
    }
    else
    {
        tmp -> next = l2;
    }
    return head -> next;
}
};

 

leetcode [64] merge tow sorted lists

标签:des   style   blog   io   color   sp   for   strong   div   

原文地址:http://www.cnblogs.com/higerzhang/p/4099726.html

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