标签:des io ar os sp for on art 代码
可能是因为我是按难度顺序刷的原因,这个其实在之前的几道题里面已经写过了。题目如下:
Given a binary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
然后就直接拿之前的代码了:
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: int maxDepth(TreeNode *root) { if (root == NULL) return 0; else { int aspros = maxDepth(root->left); int defteros = maxDepth(root->right); return 1 + (aspros>defteros ? aspros : defteros); } } };
非常简单,重复复用。
[leetcode] 8. Maximum Depth of Binary Tree
标签:des io ar os sp for on art 代码
原文地址:http://www.cnblogs.com/TinyBox/p/4100198.html