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Leetcode-Unique Paths II

时间:2014-11-17 06:53:34      阅读:138      评论:0      收藏:0      [点我收藏+]

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Follow up for "Unique Paths":

Now consider if some obstacles are added to the grids. How many unique paths would there be?

An obstacle and empty space is marked as 1 and 0 respectively in the grid.

For example,

There is one obstacle in the middle of a 3x3 grid as illustrated below.

[
  [0,0,0],
  [0,1,0],
  [0,0,0]
]

The total number of unique paths is 2.

Note: m and n will be at most 100.

Analysis:

DP problem. Similiar to Unique Path I.

Solution:

 1 public class Solution {
 2     public int uniquePathsWithObstacles(int[][] obstacleGrid) {
 3         int[][] grid = obstacleGrid;
 4         int xLen = grid.length;
 5         if (xLen==0) return 0;
 6         int yLen = grid[0].length;
 7         if (yLen==0) return 0;
 8         
 9         int[] path = new int[yLen];
10         if (grid[0][0]==1)
11             return 0;
12         else path[0] = 1;
13         for (int i=1;i<yLen;i++)
14            if (grid[0][i]==1) path[i]=0;
15            else path[i] = path[i-1];
16         
17         for (int i=1;i<xLen;i++){
18             if (grid[i][0]==1) path[0] = 0;
19             for (int j=1;j<yLen;j++)
20                 if (grid[i][j]==1) path[j] = 0;
21                 else path[j] = path[j-1]+path[j];
22         }
23         return path[yLen-1];              
24         
25     }
26 }

 

Leetcode-Unique Paths II

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原文地址:http://www.cnblogs.com/lishiblog/p/4102791.html

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