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leetcode Unique Paths

时间:2014-11-17 12:13:51      阅读:184      评论:0      收藏:0      [点我收藏+]

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A robot is located at the top-left corner of a m x n grid (marked ‘Start‘ in the diagram below).

The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked ‘Finish‘ in the diagram below).

How many possible unique paths are there?

因为只能向下或者向右走,所依某一点的值就是上面方格的值 和左边的值 相加

dynamic programming.

public class Solution {
    public int uniquePaths(int m, int n) {
        int[][] grid=new int[100][100];
        for(int i=0;i<m;i++){
        	grid[i][0]=1;
        }
        for(int j=0;j<n;j++){
        	grid[0][j]=1;
        }
        for(int i=1;i<m;i++){
        	for(int j=1;j<n;j++){
        		grid[i][j]=grid[i-1][j]+grid[i][j-1];
        	}
        }
        return grid[m-1][n-1];
    }
}

  

leetcode Unique Paths

标签:blog   io   ar   os   sp   java   for   div   on   

原文地址:http://www.cnblogs.com/lilyfindjobs/p/4103068.html

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