People in Silverland use square coins. Not only they have square shapes but also their values are square numbers. Coins with values of all square numbers up to 289 (=17^2), i.e., 1-credit coins, 4-credit coins, 9-credit coins, ..., and 289-credit coins, are available in Silverland. 
There are four combinations of coins to pay ten credits: 

ten 1-credit coins,
one 4-credit coin and six 1-credit coins,
two 4-credit coins and two 1-credit coins, and
one 9-credit coin and one 1-credit coin. 

Your mission is to count the number of ways to pay a given amount using coins of Silverland.

The input consists of lines each containing an integer meaning an amount to be paid, followed by a line containing a zero. You may assume that all the amounts are positive and less than 300.

For each of the given amount, one line containing a single integer representing the number of combinations of coins should be output. No other characters should appear in the output. 

2
10
30
0

1
4
27
/*仍然是母函数，只需改成k+=i*i就行。 
*/
#include<stdio.h>
int a[310],s[310];
int main()
{
	int i,j,k,n;
	while(scanf("%d",&n),n)
	{
		for(i=0;i<=n;i++)
		{
			a[i]=0;
			s[i]=1;
		}
		for(i=2;i<=n;i++)
		{
			for(j=0;j<=n;j++)
			{
				for(k=0;k+j<=n;k+=i*i)
				a[k+j]+=s[j];
			}
			for(j=0;j<=n;j++)
			{
				s[j]=a[j];
				a[j]=0;
			}
		}
		printf("%d\n",s[n]);
	}
	return 0;
}