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Unique Paths

时间:2014-11-20 14:57:16      阅读:196      评论:0      收藏:0      [点我收藏+]

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Dynamic Programming

A robot is located at the top-left corner of a m x n grid (marked ‘Start‘ in the diagram below).

The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked ‘Finish‘ in the diagram below).

How many possible unique paths are there?

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Above is a 3 x 7 grid. How many possible unique paths are there?

Note: m and n will be at most 100.

C++代码:

#include<iostream>
using namespace std;

class Solution {
public:
    int uniquePaths(int m, int n) {
        if(m==0||n==0)
            return 0;
        int path[m][n];
        path[0][0]=0;
        int i,j;
        for(i=0;i<m;i++)
            path[i][0]=1;
        for(j=0;j<n;j++)
            path[0][j]=1;
        for(i=1;i<m;i++)
        {
            for(j=1;j<n;j++)
                path[i][j]=path[i-1][j]+path[i][j-1];
        }
        return path[m-1][n-1];
    }
};

int main()
{
    Solution s;
    cout<<s.uniquePaths(3,7)<<endl;
}

 

Unique Paths

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原文地址:http://www.cnblogs.com/wuchanming/p/4110439.html

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