标签:style blog http io ar color os sp for
题目链接:http://poj.org/problem?id=2976
题意:给定A数组和B数组,从中选n-k对数,使得题目里给的表达式的值最小
思路:01分数规划
参考链接:http://blog.csdn.net/hhaile/article/details/8883652
代码:
#include<cstdio> #include<iostream> #include<cstring> #include<algorithm> #include<cstdlib> using namespace std; const int maxn = 1e6+10; double eps = 1e-6; struct node { double u, v; } b[maxn]; int n, m, k; double xx, ans; bool cmp(node a, node b) { return a.u-xx*a.v>b.u-xx*b.v; } double check(double x) { xx = x; ans = 0; nth_element(b, b+k-1, b+n, cmp); for(int i=0; i<k; i++) { ans += b[i].u-xx*b[i].v; } return ans; } int main() { //freopen("test.txt", "r", stdin); while(scanf("%d %d", &n, &m)!=EOF) { if(n==0 && m==0) break; k = n-m; for(int i=0; i<n; i++) { scanf("%lf", &b[i].u); } for(int i=0; i<n; i++) { scanf("%lf", &b[i].v); } double l=0, r=1e7, mid; while(l<r) { double mid=(l+r)/2; if(check(mid)<-eps) r=mid-eps; else l=mid+eps; } printf("%.0lf\n", 100*xx); } return 0; }
标签:style blog http io ar color os sp for
原文地址:http://www.cnblogs.com/sayeter/p/4111558.html