标签:style blog http io ar color os sp for
http://acm.hdu.edu.cn/showproblem.php?pid=4407
题意:给定初始n个数1..n,两个操作,①1 x y p 询问第x个数到第y个数中与p互质的数的和; ②:2 x y 把第x个数变成y;
思路:
把p分解质因子,然后找出(1,pos)内与p不互质的,然后用的减去就是互质的和,第二个操作用到map映射,记录在那个位置改变之后的数。
1 #include <cstdio> 2 #include <cstring> 3 #include <map> 4 #include <vector> 5 #include <algorithm> 6 #define LL __int64 7 #define maxn 400001 8 using namespace std; 9 10 int t; 11 int n,m; 12 13 LL gcd(LL a,LL b) 14 { 15 return b==0?a:gcd(b,a%b); 16 } 17 18 19 LL deal(LL x,LL y) 20 { 21 LL res=x*(x+1)/2; 22 vector<int>p; 23 for(int i=2; i*i<=y; i++) 24 { 25 if(y%i==0) 26 { 27 p.push_back(i); 28 while(y%i==0) 29 { 30 y/=i; 31 } 32 } 33 } 34 if(y>1) p.push_back(y); 35 LL ans=0; 36 for(int i=1; i<(1<<((int)p.size())); i++) 37 { 38 LL xx=0; 39 LL c=1; 40 for(int j=0; j<(int)p.size(); j++) 41 { 42 if(i&(1<<j)) 43 { 44 xx++; 45 c*=p[j]; 46 } 47 } 48 LL t=x/c; 49 LL sum=((t+1)*t/2)*c; 50 if(xx%2) 51 { 52 ans+=sum; 53 } 54 else 55 ans-=sum; 56 } 57 return res-ans; 58 } 59 60 int main() 61 { 62 map<int,int>q; 63 scanf("%d",&t); 64 while(t--) 65 { 66 q.clear(); 67 scanf("%d%d",&n,&m); 68 int x,y,op,pp; 69 for(int i=1; i<=m; i++) 70 { 71 scanf("%d",&op); 72 if(op==1) 73 { 74 scanf("%d%d%d",&x,&y,&pp); 75 LL sum=deal((LL)y,(LL)pp)-deal((LL)(x-1),(LL)pp); 76 map<int,int>::iterator it=q.begin(); 77 while(it!=q.end()) 78 { 79 if(it->first>=x&&it->first<=y) 80 { 81 if(gcd(it->first,pp)==1) 82 { 83 sum-=it->first; 84 } 85 if(gcd(it->second,pp)==1) 86 { 87 sum+=it->second; 88 } 89 } 90 it++; 91 } 92 printf("%I64d\n",sum); 93 } 94 else 95 { 96 scanf("%d%d",&x,&y); 97 q[x]=y; 98 } 99 } 100 } 101 return 0; 102 }
标签:style blog http io ar color os sp for
原文地址:http://www.cnblogs.com/fanminghui/p/4113650.html